定积分的应用。

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2022-12-17 18:37:40 +08:00
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commit 6a9949dbec
4 changed files with 238 additions and 11 deletions

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@@ -37,7 +37,7 @@
\end{corollary}
\begin{corollary}
$\vert f \vert, f \in R[a,b]$,则
$\abs{f}, f \in R[a,b]$,则
\[\left| \int_a^b f(x) \dif x \right| \leq \int_a^b \vert f(x) \vert \dif x \eqper\]
\end{corollary}
@@ -121,18 +121,18 @@
使得
\[\left|\sum_{i=1}^n f(c_i) \Delta x - A\right| < 1, c_i \in [x_{i-1}, x_i]\text{任取}, i = 1, 2, \cdots, n\]
由此导出
\[\left|\sum_{i=1}^n f(c_i) \Delta x \right| < \left|\sum_{i=1}^n f(c_i) \Delta x - A\right| + \vert A \vert < 1 + \vert A \vert\]
\[\left|\sum_{i=1}^n f(c_i) \Delta x \right| < \left|\sum_{i=1}^n f(c_i) \Delta x - A\right| + \abs{A} < 1 + \abs{A}\]
因此
\[\left|\sum_{i=1}^n f(c_i) \right| \leq \frac{1 + \vert A \vert}{\Delta x}\]
\[\left|\sum_{i=1}^n f(c_i) \right| \leq \frac{1 + \abs{A}}{\Delta x}\]
进一步有
\[\vert f(c_i) \vert \leq \left| \sum_{i=1}^n f(c_i) \right| + \left| \sum_{i=2}^n f(c_i)\right| \leq \frac{1 + \vert A \vert}{\Delta x} + \left| \sum_{i=2}^n f(x_i) \right|\]
\[\vert f(c_i) \vert \leq \left| \sum_{i=1}^n f(c_i) \right| + \left| \sum_{i=2}^n f(c_i)\right| \leq \frac{1 + \abs{A}}{\Delta x} + \left| \sum_{i=2}^n f(x_i) \right|\]
\[\vert f(x) \vert \leq \frac{1 + \vert A \vert}{\Delta x} + \left|\sum_{i\neq 1}^n f(x_i)\right| = M_1, \forall x \in [x_0, x_1]\]
\[\vert f(x) \vert \leq \frac{1 + \abs{A}}{\Delta x} + \left|\sum_{i\neq 1}^n f(x_i)\right| = M_1, \forall x \in [x_0, x_1]\]
类似地可以得到
\begin{align*}
\vert f(x) \vert \leq \frac{1 + \vert A \vert}{\Delta x} + \left|\sum_{i\neq 2}^n f(x_i)\right| & = M_2, \forall x \in [x_1, x_2]\\
\vert f(x) \vert \leq \frac{1 + \abs{A}}{\Delta x} + \left|\sum_{i\neq 2}^n f(x_i)\right| & = M_2, \forall x \in [x_1, x_2]\\
\vdots & \\
\vert f(x) \vert \leq \frac{1 + \vert A \vert}{\Delta x} + \left|\sum_{i\neq n}^n f(x_i)\right| & = M_n, \forall x \in [x_{n-1}, x_n]
\vert f(x) \vert \leq \frac{1 + \abs{A}}{\Delta x} + \left|\sum_{i\neq n}^n f(x_i)\right| & = M_n, \forall x \in [x_{n-1}, x_n]
\end{align*}
将这$n$个式子综合起来就可以得到
\[\vert f(x) \vert \leq \max \{M_1, \cdots, M_n\}, \forall x \in [a,b] \eqper \qedhere\]
@@ -521,7 +521,7 @@ C^n [a,b] = \{f \in C[a,b] \mid f^{(n)} \in C[a,b]\}\]
\begin{corollary}
容易由Lebesgue定理得到以下结论
\begin{enumerate}
\item$f \in R[a,b]$,则$\vert f \vert \in R[a,b]$
\item$f \in R[a,b]$,则$\abs{f} \in R[a,b]$
\item$f, g \in R[a,b]$,则$fg \in R[a,b]$
\item$f \in R[a,b]$$\dfrac{1}{f}$有界,则$\dfrac{1}{f} \in R[a,b]$
\item$f \in R[a,b], \varphi \in C[\alpha, \beta]$$f([a,b]) \subset [\alpha, \beta]$,则$\varphi \circ f \in R[a,b]$
@@ -609,7 +609,7 @@ C^n [a,b] = \{f \in C[a,b] \mid f^{(n)} \in C[a,b]\}\]
\end{definition}
\begin{lemma}[Riemann-Lebesgue]
$f$$[a,b]$上可积或广义绝对可积($f$$\vert f \vert$均在$[a,b]$上广义可积),则
$f$$[a,b]$上可积或广义绝对可积($f$$\abs{f}$均在$[a,b]$上广义可积),则
\[\tolim{\lambda}{\infty} \int_a^b f(x) \cos \lambda x \dif x = 0, \tolim{\lambda}{\infty} \int_a^b f(x) \sin \lambda x \dif x = 0\eqper\]
\end{lemma}
@@ -646,4 +646,4 @@ C^n [a,b] = \{f \in C[a,b] \mid f^{(n)} \in C[a,b]\}\]
\left|\int_a^b f(x) \cos \lambda x \dif x \right| & \leq \left|\int_a^{a + \delta} f(x) \cos x \lambda x \dif x \right| + \left|\int_{a + \delta}^b f(x) \cos \lambda x \dif x \right|\\
& < \frac{\varepsilon}{2} = \frac{\varepsilon}{2} = \varepsilon\eqper \qedhere
\end{align*}
\end{proof}
\end{proof}